\(x=\sqrt{x}<=>x-\sqrt{x}=0=>x\left(\sqrt{x}-1\right)=0=>x=0;\sqrt{x}=1=>x=1\)
vây x E {0;1}
$x=\sqrt{x}<=>x-\sqrt{x}=0=>x\left(\sqrt{x}-1\right)=0=>x=0;\sqrt{x}=1=>x=1$
x=\(\sqrt{x}\)
x=\(\sqrt{x}\) \(\Rightarrow\) x \(\notin\) \(Z^-\)
x=\(\sqrt{x}\)\(\Rightarrow\)\(x^2=x\)
Ta suy ra x=0;1