=>|x-1|=17-15=2
TH2:x-1=2
=>x=2+1=3
TH2:x-1=-2
=>x=-2+1=-1
Vậy x E {3;-1}
= [X-1]=17-15
=[X-1]=+-2
TA CÓ :KHI X-1=2 =>X=3
KHI X-1=-2 =>X=-1
! x-1 ! =17-15
!x-1! = 2
\(\Rightarrow\hept{\begin{cases}x-1=2\\x-1=-2\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=2+1\\x=-2+1\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=3\\x=-1\end{cases}}\)
Vậy \(x\in\left(-1;3\right)\)
\(\Rightarrow\left|x-1\right|=17-15\)
\(\left|x-1\right|=2\)
\(\orbr{\begin{cases}x-1=-2\\x-1=2\end{cases}\Rightarrow}\orbr{\begin{cases}x=-1\\x=3\end{cases}}\)
Vậy x thuộc -1;3