ĐKXĐ: \(x\ge0\)
\(pt\Leftrightarrow\sqrt{x}\left(1+2\sqrt{x}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=0\\1+2\sqrt{x}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\\sqrt{x}=-\frac{1}{2}\left(\text{vô nghiệm}\right)\end{matrix}\right.\)
\(\Leftrightarrow x=0\)