b)Có \(63^7< 64^7\)
\(64^7=\left(2^6\right)^7=2^{42}\)
\(16^{12}=\left(2^4\right)^{12}=2^{48}\)
Mà \(2^{42}< 2^{48}\Rightarrow63^7< 64^7< 16^{12}\Rightarrow63^7< 16^{12}\)
tính hợp lý:
a) \(\left(\frac{9}{10}-\frac{15}{16}\right)\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)
b) \(\left(\frac{1}{2}-1\right)\left(\frac{1}{3-1}\right)\left(\frac{1}{4}-1\right).......\left(\frac{1}{100}-1\right)\)
So sánh A và B biết:
\(A=\frac{10^{15}+1}{10^{16}+1}\)và \(B=\frac{10^{16}+1}{10^{17}+1}\)
Tính:
A=\(\frac{3}{4}+\frac{8}{9}+\frac{15}{16}+...+\frac{3590}{3600}\)
B=\(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{6}\right).\left(1-\frac{1}{10}\right)......\left(1-\frac{1}{780}\right)\)
Giải nhanh giùm mình!!!!
So sánh A và B biết:\(A=\frac{10^{15}+1}{10^{16}+1}vàB=\frac{10^{16}+1}{10^{17}+1}\)
a)Tính\(\frac{\left(17\frac{8}{19}-16\frac{9}{18}\right)\left(17,5+16\frac{17}{51}-32\frac{15}{22}\right)}{\frac{7}{3.13}+\frac{7}{13.23}+\frac{7}{23.33}}\)
b) Chứng tò rằng:\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}\)\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
Tính:
a, \(\frac{-28}{19}.\frac{\left(-38\right)}{14}\)
b, \(\frac{-21}{16}.\frac{\left(-24\right)}{7}\)
c, \(\frac{12}{17}.\frac{\left(-34\right)}{9}\)
d, \(\frac{\left(-15\right)}{4}:\frac{21}{10}\)
e,\(-2\frac{1}{7} :-1\frac{1}{14}\)
So sánh lũy thừa sau:
a)(\(\frac{1}{31}\))\(^7\)và (\(\frac{1}{17}\))\(^9\)
b)A=\(\frac{10^{15}+1}{10^{16}+1}\) và B=\(\frac{10^{16}+1}{10^{17}+1}\)
Mk đang cần gấp,ai nhanh mk sẽ tick nha =))))
So sánh:
\(A=\frac{10^{15}+1}{10^{16}+1}\)và \(B=\frac{10^{16}+1}{10^{17}+1}\)
so sánh A và B biết:
A=\(\frac{10^{15}+1}{10^{16}+1}\)
B=\(\frac{10^{16}+1}{10^{17}+1}\)
