A. \(3^{24680}\)và \(2^{37020}\)
\(3^{24680}=\left(3^2\right)^{12340}=9^{12340}\)
\(2^{37020}=\left(2^3\right)^{37020}=8^{12340}\)
Vì \(8< 9\Rightarrow8^{12340}< 9^{12340}\)
\(\Rightarrow3^{24680}>2^{37020}\)
\(B.3^{2n}\)và \(2^{3n}\)
\(3^{2n}=9^n\)
\(2^{3n}=8^n\)
\(Vì\)\(8< 9\Rightarrow8^n< 9^n\)
\(\Rightarrow3^{2n}>2^{3n}\)
học tốt
so sanh phan so:
a) n/n + 3 va n - 1/n+4 ( n thuoc N)
b) n/n + 1 va n + 2/n + 3
c) n/2n + 1 va 3n + 1/6n + 3 ( n thuoc N)
so sanh 32n va 23n voi n thuoc N*
so sanh :32n va 23n(n thuoc N*)
ai tick minh minh tick lai
Giúp mình bài này :
Chung minh rang 2 so 2n+3 va 3n+4 voi n thuoc N la 2 so nguyen to cung nhau
chung minh rang 2n+3 va 3n+5 la hai so nguyen to cung nhau (n thuoc N*)
tim n thuoc N de 3n2 +2n+3 va 2n+1 nguyen to cung nhau
tim uc cua 2n+3 va 3n+1 voi n thuoc N
tim n thuoc Z de
a)n+3/n-2 la so nguyen am
b)n+7/3n-1 la so tu nhien
c)3n+2/4n-5 la so tu nhien
d)15/n ; 12/n+2 va 6/2n-5 deu la so nguyen
ai giai duoc,trinh bay day du mik tick cho(mik can gap)
chung to 2 so sau la 2 so nguyen to cung nhau
a,2n+3 va n+2
b,3n+1va 2n+1
c,n+10 va n+11
