Question

So sánh

1-\(\frac{1}{\sqrt{8}}\)và \(\frac{3}{4}\)

Answer 1

Ta có: \(\frac{1}{8}>\frac{1}{9}\) => \(\sqrt{\frac{1}{8}}>\sqrt{\frac{1}{9}}\)hay \(\frac{1}{\sqrt{8}}>\frac{1}{\sqrt{9}}=\frac{1}{3}\)

=> \(1-\frac{1}{\sqrt{8}}< 1-\frac{1}{3}\)

\(\frac{3}{4}=1-\frac{1}{4}\)

Do \(\frac{1}{3}>\frac{1}{4}\) => \(1-\frac{1}{3}< 1-\frac{1}{4}\)

hay \(1-\frac{1}{\sqrt{8}}< \frac{3}{4}\)

Answer 2

Bài làm:

Ta có: \(1-\frac{1}{\sqrt{8}}< 1-\frac{1}{\sqrt{9}}=1-\frac{1}{3}< 1-\frac{1}{4}=\frac{3}{4}\)

\(\Rightarrow1-\frac{1}{\sqrt{8}}< \frac{3}{4}\)