Chứng minh rằng
\(\frac{1}{15}+\frac{1}{16}+\frac{1}{17}+...+\frac{1}{43}+\frac{1}{44}>\frac{5}{6}\)
a) \(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\)
b) \(\frac{\frac{15}{12}+\frac{3}{4}-1}{3-\frac{5}{6}+\frac{2}{3}}+\frac{\frac{16}{5}+\frac{16}{7}-\frac{16}{9}}{\frac{17}{5}+\frac{17}{7}-\frac{17}{9}}\)
So sanh A và B :
\(A=\frac{10^{15}+1}{10^{16}+1}\); \(B=\frac{10^{16}+1}{10^{17}+1}\)
so sanh A va B bit
A=\(\frac{1}{3}+\frac{1}{4}+...+\frac{1}{17}\)
B=\(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2010}\)
so sánh:
1)\(\frac{10^{11}-1}{10^{12}-1}\)và \(\frac{10^{10}+1}{10^{11}+1}\)
2) \(\frac{54.107-53}{53.107-54}\)và \(\frac{135.269-133}{135.269+135}\)
3)\(\frac{1}{15}+\frac{1}{16}+\frac{1}{17}+...+\frac{1}{43}+\frac{1}{44}và\frac{5}{6}\)
so sánh
a, A=\(\frac{10^{17}-1}{10^{16}-1}vaB=\frac{10^{16}+2}{10^{15}+2}\)
b,\(C=\frac{2017^{15}+1}{2017^{16}+1}vaO=\frac{2017^{16}-1}{2017^{17}-1}\)
c,\(E=\frac{99^{15}-1}{99^{16}-1}vaF=\frac{99^{16}+2}{99^{17}+2}\)
\(A=\frac{1}{4}.\frac{3}{6}.\frac{5}{8}....\frac{43}{46}.\frac{45}{48}\)
\(B=\frac{2}{5}.\frac{4}{7}.\frac{6}{9}....\frac{44}{47}.\frac{46}{49}\)
a) So sánh A và B
b) Chứng minh A<133
\(A=\frac{1}{4}.\frac{3}{6}.\frac{5}{8}....\frac{43}{46}.\frac{45}{48}\)
\(B=\frac{2}{5}.\frac{4}{7}.\frac{6}{9}....\frac{44}{47}.\frac{46}{49}\)
a) So sánh A và B
b) Chứng minh A<133
Chứng minh rằng
\(\frac{1}{5}+\frac{1}{16}+\frac{1}{17}+...+\frac{1}{44}+\frac{1}{45}>\frac{5}{6}\)