\(A=\frac{19^{30}+5}{19^{31}+5}=>19A=\frac{19^{31}+95}{19^{31}+5}=1+\frac{90}{19^{31}+5}\left(1\right)\)
\(B=\frac{19^{31}+5}{19^{32}+5}=>19B=\frac{19^{32}+95}{19^{32}+5}=1+\frac{90}{19^{32}+5}\left(2\right)\)
từ (1) and (2)
=>19A>19B
=>A>B
Ta có:
19A=19^31+95/19^31+5
19A= (19^31+5)+90/19^31+5
19A=1+90/19^31+5
19B=19^32+95/19^32+5
19B=(19^32+5)+90/19^32+5
19B=1+90/19^32+5
Vì: 90/19^31+5>90/19^31+5 nên 19A>19B hay A>B