\(A=\frac{17^{18}+1}{17^{19}+1}\)
\(\Leftrightarrow17A=\frac{17^{19}+17}{17^{19}+1}\)
\(\Leftrightarrow17A=\frac{17^{19}+1+16}{17^{19}+1}\)
\(\Leftrightarrow17A=\frac{17^{19}+1}{17^{19}+1}+\frac{16}{17^{19}+1}\)
\(\Leftrightarrow17A=1+\frac{16}{17^{19}+1}\)
\(B=\frac{17^{17}+1}{17^{18}+1}\)
\(\Leftrightarrow17B=\frac{17^{18}+17}{17^{18}+1}\)
\(\Leftrightarrow17B=\frac{17^{18}+1+16}{17^{18}+1}\)
\(\Leftrightarrow17B=\frac{17^{18}+1}{17^{18}+1}+\frac{16}{17^{18}+1}\)
\(\Leftrightarrow17B=1+\frac{16}{17^{18}+1}\)
Vì \(1+\frac{16}{17^{18}+1}>1+\frac{16}{17^{19}+1}\) nên 17B > 17A
Suy ra B > A
Thanks nha
Xin lỗi mình kh thể viết theo công thức đc😅😅😅😅