Question

so sánh 19^10+1/19^11+1 và 19^19+1/19^20+1
Ai giúp với gấp lắm r

Answer 1

brr brrr

Answer 2

Đặt \(A=\frac{19^{10}+1}{19^{11}+1};B=\frac{19^{19}+1}{19^{20}+1}\)

\(19A=\frac{19^{11}+19}{19^{11}+1}=1+\frac{18}{19^{11}+1}\)

\(19B=\frac{19^{20}+19}{19^{20}+1}=\frac{19^{20}+1+18}{19^{20}+1}=1+\frac{18}{19^{20}+1}\)

Ta có: \(19^{11}+1<19^{20}+1\)

=>\(\frac{18}{19^{11}+1}>\frac{18}{19^{20}+1}\)

=>\(\frac{18}{19^{11}+1}+1>\frac{18}{19^{20}+1}+1\)

=>19A>19B

=>A>B

Answer 3

ngồi bấm máy đi