Ta có: 22/33 = 2/3 = 12/18
12/19 < 12/18
Vậy 12/19 < 22/33
\(\frac{1212}{1313}=\frac{101.12}{101.13}=\frac{12}{13}\)
12/13 = 12/13
Vậy 12/13 = 1212/1313
124124/125125 = \(\frac{1001.124}{1001.125}=\frac{124}{125}\)
1 - 123/124 = 1/124 ; 1 - 124/125 = 1/125
Nên 123/124 < 124/125
Vậy 123/124 < 124124/125125
a) Ta có : 22/33 = 2/3 = 12/18
Vì 12/18 > 12/19 nên 12/19 < 22/33
b) Ta có : 1212/1313 = 12/13
Vì 12/13 = 12/13 nên 12/13 = 1212/1313
c) Ta có : 124124/125125 = 124/125
1 - 123/124 = 1/124
1 - 124/125 = 1/125
Vì 1/124 > 1/125 nên 123/124 < 124124/125125