Có \(\frac{-42}{7}=-6\) ; \(\frac{-24}{6}=-4\)nên ta có \(-6< x< -4\)
Do \(x\inℤ\)nên \(x=-5\)
Vậy \(x=-5\)
Có \(\frac{-42}{7}=-6\) ; \(\frac{-24}{6}=-4\)nên ta có \(-6< x< -4\)
Do \(x\inℤ\)nên \(x=-5\)
Vậy \(x=-5\)
so cap so nguyen x,y thoa man dieu kien 3/x+y/3=5/6 la ... cap
Tìm tập hop cac so nguyen x thoa man cac dieu kien sau
a)7/2 . 5/12 - 1 < x < 23/3 ÷ 7/3 + 5/7
b)-2240/6 x + 3 ÷5/3 la so nguyen
tim cac so nguyen x,y,z thoa man dieu kien sau
x^2=y-1
y^2=z-1
z^2=x-1
cac so nguyen a,b thoa man dieu kien gi de : a+b =- ( |a|- |b| )
tim so tu nhien a be nhat thoa man dieu kien \(\frac{20}{a}\)<\(\frac{4}{5}\)
so cac cap so tu nhien (x;y) thoa man dieu kien: (x+3)(y+2)=20
tim cac so tu nhien a,b thoa man dieu kien \(\frac{11}{17}<\frac{a}{b}<\frac{23}{29}\)va 8b-9a=31
tim cac so tu nhien a,b thoa man dieu kien \(\frac{11}{17}\)<\(\frac{A}{B}\)<\(\frac{23}{29}\)
co ton tai hay ko so nguyen a,b,c thoa man tat ca cac dieu kien sau abc + a = -625 , abc + b = -633 , abc + c = -597