\(1+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=\frac{43}{30}\)
\(\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=\frac{43}{30}-1\)
\(\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=\frac{13}{30}\)
Ta có:\(\frac{13}{30}=\frac{1}{\frac{30}{13}}=\frac{1}{2+\frac{4}{13}}=\frac{1}{2+\frac{1}{\frac{13}{4}}}=\frac{1}{2+\frac{1}{3+\frac{1}{4}}}\)
Vậy x=2; y=3; z=4