\(S=1+3+3^2+3^3+...+3^{48}+3^{49}.\)
\(S=\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{48}+3^{49}\right)\)
\(S=1\left(1+3\right)+3^2\left(1+3\right)+..+3^{48}\left(1+3\right)\)
\(S=4\left(1+3^2+....+3^{48}\right)\)
\(\Rightarrow S⋮4\)
b, Có : \(S=1+3+3^2+3^3+...+3^{48}+3^{49}\)
\(\Rightarrow3S=3+3^2+3^3+...+3^{48}+3^{49}+3^{50}\)
=> 3S - S = ( 1 + 3 + 32 + 33 + ..... + 348 + 349 ) - ( 3 + 33 + 33 + .. + 349 + 350)
\(\Rightarrow2S=3^{50}-1\)
\(\Rightarrow S=\frac{3^{50}-1}{2}\)
\(\Rightarrow3^{50}-1=\left(...9\right)-1=\left(...8\right)\)( tận cùng là 8 )
\(\Rightarrow S=\frac{3^{50}-1}{2}=\frac{....8}{2}=\left(...4\right)\)
=> S có tận cùng là 4
a) \(S=1+3+3^2+3^3+...+3^{48}+3^{49}\)
\(S=\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{48}+3^{49}\right)\)
\(S=4+\left(3^2.1+3^2.3\right)+...+\left(3^{48}.1+3^{48}.3\right)\)
\(S=4+3^2.\left(1+3\right)+...+3^{48}.\left(1+3\right)\)
\(S=1.4+3^2.4+...+3^{48}.4\)
\(S=\left(1+3^2+....+3^{48}\right).4⋮4\)
a)S= (1+3)+(32+33)+...+(348+349)
S=4+32.(1+3)+...+348.(3+1)
S=4+32.4+.....+348.4
S=4.(1+32+...+348)
=> S chia hết cho 4
a) Ta có
3S= 3+32+34+35+36+37+38+....+348+349+350
3S-S= 350-3
3S-S=2S=>2S= 350-3
Vậy S= (350-3):2
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