\(=\left(x-\dfrac{1}{2}\right)^2\cdot\left(x+\dfrac{1}{2}\right)^2\)
\(=\left(x^2-\dfrac{1}{4}\right)^2\)
\(=x^4-\dfrac{1}{2}x^2+\dfrac{1}{16}\)
giải pt sau
g) 11+8x-3=5x-3+x
h)4-2x+15=9x+4-2x
g)\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
h)\(\dfrac{x+4}{5}-x+4=\dfrac{4x+2}{5}-5\)
i)\(\dfrac{4x+3}{5}-\dfrac{6x-2}{7}=\dfrac{5x+4}{3}+3\)
k) \(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
m) \(\dfrac{2x-1}{5}-\dfrac{x-2}{3}=\dfrac{xx+7}{15}\)
n)\(\dfrac{1}{4}\left(x+3\right)=3-\dfrac{1}{2}\left(x+1\right)-\dfrac{1}{3}\left(x+2\right)\)
p)\(\dfrac{x}{3}-\dfrac{2x+1}{6}=\dfrac{x}{6}-x\)
q)\(\dfrac{2+x}{5}-0,5x=\dfrac{1-2x}{4}+0,25\)
1) Rút gọn
a) (3x - 2)2 - (1+ 5x)2
b) (3x + 4)(3x - 4) - (5 - x)2
c) (\(\dfrac{1}{2}\)x + 4)2 - (\(\dfrac{1}{2}\)x + 3)(\(\dfrac{1}{2}\)x - 3)
Rút gọn một biểu thức :
\(F=\dfrac{1}{1-x}+\dfrac{1}{1+x}+\dfrac{2}{1+x^2}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}\left(x\ne1và-1\right)\)
tìm x biết
a, ( x + 5 )2 - ( x - 3 )2 = 2x - 7
b, ( 2x - 3 ) . ( 4x2 + 6x + 9 ) = 98
c, ( \(\dfrac{1}{9}\)x2 + \(\dfrac{2}{3}\)x + 4 ) . ( \(\dfrac{1}{3}\)x - 2 ) = 56
d, 16x3 - 12x2 + 3x - 7 = 0
a. \(\dfrac{x-1}{x^{2^{ }}-4}=\dfrac{3}{2-x}\)
b. \(\dfrac{1}{x-1}-\dfrac{7}{x-2}=\dfrac{1}{\left(x-1\right)\left(2-x\right)}\)
c. \(\dfrac{2x+3}{2x-3}-\dfrac{3}{4x-6}=\dfrac{2}{5}\)
d. \(\dfrac{x+29}{31}-\dfrac{x+27}{33}=\dfrac{x+17}{43}-\dfrac{x+15}{45}\)
tìm GTNN
c) D = x2-x+\(\dfrac{1}{2}\)
giải phương trình : \(\dfrac{x-4}{x-1}\)+ \(\dfrac{x+4}{x+1}\) = 2
x2+\(\dfrac{1}{4}\)-x giúp mình với
RÚT GỌN CÁC BIỂU THỨC SAU:
a)A=(x-y)^2+(x+y)^2
b)B=(x+y)^2-(x-y)^2
c)C=(2a+b)^2-(2a-b)^2
d)D= (2x-1)^2-2(2x-3)^2+4
e)E=(x+3y)^2-(x-3y)^2
f)F=(2x+y)^2-(2x-y)^2
g)G=(x-2y)^2+4(x-2y)y+4y^2
h)H=(x-y)^2-4(x-y)(x+2y)+4(x+2y)^2
