Các câu hỏi tương tự
Bài 1: Tính giá trị của biểu thức: 1)Hsqrt[3]{3+sqrt{9+frac{125}{7}}}-sqrt[3]{-3+sqrt{9+frac{125}{7}}} 2)Pfrac{2}{sqrt{4-3sqrt[4]{5}+2sqrt{5}-sqrt[4]{125}}}Bài 2: Tính giá trị biểu thức: Qsqrt[10]{frac{19+6sqrt{10}}{2}}.sqrt[5]{3sqrt{2}-2sqrt{5}} Kfrac{sqrt{sqrt[4]{8}+sqrt{sqrt{2}-1}}-sqrt{sqrt[4]{8}-sqrt{sqrt{2}-1}}}{sqrt{sqrt[4]{8}-sqrt{sqrt{2}+1}}}
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Bài 1: Tính giá trị của biểu thức:
1)\(H=\sqrt[3]{3+\sqrt{9+\frac{125}{7}}}-\sqrt[3]{-3+\sqrt{9+\frac{125}{7}}}\)
2)\(P=\frac{2}{\sqrt{4-3\sqrt[4]{5}+2\sqrt{5}-\sqrt[4]{125}}}\)
Bài 2: Tính giá trị biểu thức: \(Q=\sqrt[10]{\frac{19+6\sqrt{10}}{2}}.\sqrt[5]{3\sqrt{2}-2\sqrt{5}}\)
\(K=\frac{\sqrt{\sqrt[4]{8}+\sqrt{\sqrt{2}-1}}-\sqrt{\sqrt[4]{8}-\sqrt{\sqrt{2}-1}}}{\sqrt{\sqrt[4]{8}-\sqrt{\sqrt{2}+1}}}\)
Rút gọn
1) \(B=\sqrt{\sqrt{7}+6+\sqrt{13-2\sqrt{64-6\sqrt{7}}}}\)
2) \(C=\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
3) \(D=\frac{2\sqrt{3+\sqrt{5-\sqrt{13+\sqrt{48}}}}}{\sqrt{6}+\sqrt{2}}\)
tính:\(\frac{1}{\sqrt{1}-\sqrt{2}}-\frac{1}{\sqrt{2}-\sqrt{3}}+\frac{1}{\sqrt{3}-\sqrt{4}}-\frac{1}{\sqrt{4}-\sqrt{5}}+\frac{1}{\sqrt{5}-\sqrt{6}}-\frac{1}{\sqrt{6}-\sqrt{7}}+\frac{1}{\sqrt{7}-\sqrt{8}}-\frac{1}{\sqrt{8}-\sqrt{9}}\)
Rút gọn biểu thứcA frac{sqrt{3}+sqrt{11+6sqrt{2}}-sqrt{5+2sqrt{6}}}{sqrt{2}+sqrt{6+2sqrt{5}}-sqrt{7+2sqrt{10}}}B sqrt{5sqrt{3}+5sqrt{48-10sqrt{7+4sqrt{3}}}}C sqrt{2-sqrt{3}}-sqrt{2+sqrt{3}}D sqrt{28+6sqrt{3}}-sqrt{28-6sqrt{3}}E 6x+sqrt{9x^2-12x+4}F 5x-sqrt{x^2+4x+4}
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Rút gọn biểu thức
A = \(\frac{\sqrt{3}+\sqrt{11+6\sqrt{2}}-\sqrt{5+2\sqrt{6}}}{\sqrt{2}+\sqrt{6+2\sqrt{5}}-\sqrt{7+2\sqrt{10}}}\)
B = \(\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}\)
C = \(\sqrt{2-\sqrt{3}}-\sqrt{2+\sqrt{3}}\)
D = \(\sqrt{28+6\sqrt{3}}-\sqrt{28-6\sqrt{3}}\)
E = \(6x+\sqrt{9x^2-12x+4}\)
F = \(5x-\sqrt{x^2+4x+4}\)
1. Rút gọn. a, Bsqrt{2-sqrt{2sqrt{5}-2}}-sqrt{2+sqrt{2sqrt{5}-2}} b,Cfrac{3sqrt{10}+sqrt{20}-3sqrt{6}-sqrt{12}}{sqrt{5}-sqrt{3}} c, Cfrac{sqrt{2}+sqrt{3}+sqrt{6}+sqrt{8}+sqrt{16}}{sqrt{2}+sqrt{3}+sqrt{4}}
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1. Rút gọn. a, B=\(\sqrt{2-\sqrt{2\sqrt{5}-2}}-\sqrt{2+\sqrt{2\sqrt{5}-2}}\) b,C=\(\frac{3\sqrt{10}+\sqrt{20}-3\sqrt{6}-\sqrt{12}}{\sqrt{5}-\sqrt{3}}\) c, C=\(\frac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+\sqrt{16}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
sqrt{4-sqrt{7}}-sqrt{4+sqrt{7}}+sqrt{2}sqrt{frac{2left(4-sqrt{7}right)}{2}}-sqrt{frac{2left(4+sqrt{7}right)}{2}}+sqrt{2}sqrt{frac{8-2sqrt{7}}{2}}-sqrt{frac{8+2sqrt{7}}{2}}+sqrt{2}sqrt{frac{left(sqrt{7}-1right)^2}{2}}-sqrt{frac{left(sqrt{7}+1right)^2}{2}}+sqrt{2}frac{sqrt{7}-1}{sqrt{2}}-frac{sqrt{7}+1}{sqrt{2}}+sqrt{2}frac{-2}{sqrt{2}}+sqrt{2}-sqrt{2}+sqrt{2}0
Đọc tiếp
\(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}+\sqrt{2}=\sqrt{\frac{2\left(4-\sqrt{7}\right)}{2}}-\sqrt{\frac{2\left(4+\sqrt{7}\right)}{2}}+\sqrt{2}\)
=\(\sqrt{\frac{8-2\sqrt{7}}{2}}-\sqrt{\frac{8+2\sqrt{7}}{2}}+\sqrt{2}\)
=\(\sqrt{\frac{\left(\sqrt{7}-1\right)^2}{2}}-\sqrt{\frac{\left(\sqrt{7}+1\right)^2}{2}}+\sqrt{2}\)
=\(\frac{\sqrt{7}-1}{\sqrt{2}}-\frac{\sqrt{7}+1}{\sqrt{2}}+\sqrt{2}\)
=\(\frac{-2}{\sqrt{2}}+\sqrt{2}\)
=\(-\sqrt{2}+\sqrt{2}\)
=0
\(A=\left(\sqrt{3}+1\right)^2+\frac{5}{4}\sqrt{48}-\frac{2}{\sqrt{3+1}}\)
\(B=\frac{4}{3-\sqrt{5}}-\frac{3}{\sqrt{5}+\sqrt{2}}-\frac{1}{\sqrt{2}-1}\)
\(C=\sqrt{4-2\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
Rút gọn
Giúp mình với mình cần gấp
Rút gọn
\(\frac{\sqrt{160}-\sqrt{80}}{\sqrt{8}-\sqrt{2}}-\frac{\sqrt{40}-\sqrt{15}}{2\sqrt{2}-\sqrt{3}}\)
Rút gọn biểu thức sau
a)\(\sqrt{3-\sqrt{5}}\left(\sqrt{10}-\sqrt{2}\right)\left(3+\sqrt{5}\right)\)
b)\(\sqrt{2+\sqrt{3}}\sqrt{2+\sqrt{2+\sqrt{3}}.\sqrt{2}}-\sqrt{2+\sqrt{2}}\)