\(A=\frac{x^2-2x+1}{x^2-x}-\frac{2x^3-x^2}{x^4-x^3}\)
\(A=\frac{x^2-2x+1}{x.\left(x-1\right)}-\frac{2x^3-x^2}{x^3.\left(x-1\right)}\)
\(A=\frac{x^2.\left(x^2-2x+1\right)}{x^2.x.\left(x-1\right)}-\frac{2x^3-x^2}{x^3.\left(x-1\right)}\)
\(A=\frac{x^4-2x^3+x^2}{x^3.\left(x-1\right)}+\frac{-\left(2x^3-x^2\right)}{x^3.\left(x-1\right)}\)
\(A=\frac{x^4-2x^3+x^2-2x^3+x^2}{x^3.\left(x-1\right)}\)
\(A=\frac{x^4-4x^3+2x^2}{x^3.\left(x-1\right)}\)
\(A=\frac{\left(x^4-4x^3\right)+2x^2}{x^3.\left(x-1\right)}\)
\(A=\frac{x^3.\left(x-4\right)+2x^2}{x^3.\left(x-1\right)}\)
\(A=\frac{x-4+2x^2}{x-1}.\)
Không chắc nha.
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\(\frac{x^2-2x+1}{x^2-x}-\frac{2x^3-x^2}{x^4-x^3}=\frac{\left(x-1\right)^2}{x\left(x-1\right)}-\frac{x^2\left(2x-1\right)}{x^3\left(x-1\right)}=\frac{\left(x-1\right)^2}{x^2-x}-\frac{2x-1}{x^3-x}=\frac{x^2-2x+2x+1}{x^2-x}=\frac{x^2-4x+2}{x^2-x}\)