Question

Rút gọn: 1 - Sin^2x/1+Cotx - Cos^2x/1+tanx 

Answer 1

tích mình với

ai tích mình

mình tích lại

thanks

Answer 2

Sin 1 slot xíu nữa làm

Answer 3

\(1-\frac{\sin^2x}{1+\cot x}-\frac{\cos^2x}{1+\tan x}\)

\(=1\left(\frac{\sin^2x}{1+\frac{\cos x}{\sin x}}+\frac{\cos^2x}{1+\frac{\sin x}{\cos x}}\right)\)

\(=1-\left(\frac{\sin^2x}{\frac{\sin x+\cos x}{\sin x}}+\frac{\cos^2x}{\frac{\cos x+\sin x}{\cos x}}\right)\)

\(=1-\left(\frac{\sin^3x}{\sin x+\cos x}+\frac{\cos^3x}{\sin x+\cos x}\right)\)

\(=1-\frac{\sin^3x+\cos^3x}{\sin x+\cos x}\)

\(=1-\)\(\frac{\left(\sin x+\cos x\right)\left(\sin^2x-\sin x\cos x+\cos^2x\right)}{\sin x+\cos x}\)

\(=\sin x\cos x\)