\(x^2+4x+4=\left(x+2\right)^2\)
\(3x+6=3\left(x+2\right)\)
MTC: \(3\left(x+2\right)^2\)
\(\dfrac{x+5}{x^2+4x+4}=\dfrac{\left(x+5\right).3}{\left(x+2\right)^2.3}=\dfrac{3\left(x+5\right)}{3\left(x+2\right)^2}\)
\(\dfrac{x}{3x+6}=\dfrac{x\left(x+2\right)}{3\left(x+2\right)\left(x+2\right)}=\dfrac{x\left(x+2\right)}{3\left(x+2\right)^2}\)