Question

Phân tích thành nhân tử :

x³ + 4x² - 11x + 6 .

Answer 1

\(=X^3+6x^2-2x^2-12x+x+6\\ =X^2\left(x+6\right)-2x\left(x+6\right)+\left(x+6\right)\\ =\left(x^2-2x+1\right)\left(x+6\right)\\ =\left(x-1\right)^2.\left(x+6\right)\\ \)

Vậy x=1 hoặc x=-6

Answer 2

\(x^3+4x^2-11x+6\)

\(=x^3+6x^2-2x^2-12x+x+6\)

\(=x^2\left(x+6\right)-2x\left(x+6\right)+\left(x+6\right)\)

\(=\left(x+6\right)\left(x^2-2x+1\right)\)

\(=\left(x+6\right)\left(x-1\right)^2\)