(x -y)3 - 1 - 3(x -y)(x - y - 1)
= (x -y)3 - 3(x -y)(x - y - 1) - 1
Đặt x - y = t, khi đó ta có:
t3 - 3t. (t - 1) - 1
= t3 - 3t2 + 3t - 1
= (t - 1)3
Thay t = x - y vào (t - 1)3 , ta có: ( x - y - 1)3
Vậy (x -y)3 - 1 - 3(x -y)(x - y - 1) = ( x - y - 1)3
\(\left(2x-10\right).\left(x+10\right).\left(x+\sqrt{3}\right)=0\)
(Bai phan tich da thuc thanh nhan tu)
Phan tich da thuc thanh nhan tu
\(\left(xy+4\right)^2-4\left(x+y\right)^2\)
\(x^4-4x^3+8x^2-16x+16\)
phan tich da thuc thanh nhan tu
\(9\left(x+1\right)^2-\left(3x-2\right)^2\)
phan tich da thuc thanh nhan tu
\(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24\)
ban nao giai ho mk bai nay voi
mk se tik cho
PHAN TICH DA THUC THANH NHAN TU
\(\left(x^2+6x\right).\left(x^2+14x+40\right)+128\)\
giup minh di!
\(\left(2x+1\right)^2+2\left(2x+1\right)\)
phan tich da thuc thanh nhan tu
Pha tich da thuc thanh nhan tu
\(a,6x^4-11x^2+3\)
\(b,\left(x^2+3x+1\right)\left(x^2+3x-3\right)-5\)
\(\left(3x+1\right)^2-4.\left(x-2\right)^2\)=
Giai dung nha, ai giai dung mk tick cho
Cung la bai phan tich da thuc thanh nhan tu dung hang dang thuc(cua lop 8)
phan tich da thuc thanh nhan tu
ab(a-b)+bc(b-c) +ca(c-a)
\(x^4-3x^3y+3x^2y^2-z^3-xy^3\)
\(\left(a-b\right)^3+\left(b-c\right)^3+\left(c-a\right)^3\)
