Question

Phan tich da thuc thanh nhan tu : x2 - 4x -y2+4

Answer 1

\(x^2-4x+4-y^2\)

\(=\left(x-2\right)^2-y^2\)

\(=\left(x-2-y\right)\left(x-2+y\right)\)

Answer 2

(x - 2)² - y² = (x - 2 - y)(x - 2 + y)

Answer 3

\(=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)

Answer 4

x² - 4x - y² + 4  

= x² - 4x + 4 - y²

= (x² - 2.2.x + 2²) - y²

= (x - 2)² - y²

= (x - 2 - y)(x - 2 + y)