Question

phan tich da thuc thanh nhan tu:

x² + 4x - 4y² + 8y

x³ + 2x²y + xy² - 16x

x⁴ - x -14

(x² -2x + 3)(x² - 2x +5) - 8

Answer 1

a: \(=\left(x-2y\right)\left(x+2y\right)+4\left(x-2y\right)=\left(x-2y\right)\left(x+2y+4\right)\)

b: \(=x\left(x^2+2xy+y^2-16\right)=x\left(x+y-4\right)\left(x+y+4\right)\)

d: \(=\left(x^2-2x\right)^2+8\left(x^2-2x\right)+7\)

\(=\left(x^2-2x+1\right)\left(x^2-2x+7\right)\)

\(=\left(x-1\right)^2\left(x^2-2x+7\right)\)