Question

phân tích đa thức thành nhân tử 

a,x⁴+3x³-9x-9                                                b,x³-3x²+3x-1-8y³

Answer 1

a) \(=\left(x^4-9\right)+\left(3x^3-9x\right)=\left(x^2-3\right)\left(x^2+3\right)+3x\left(x^2-3\right)=\left(x^2-3\right)\left(x^2+3x+3\right)\)

b)

\(=\left(x^3-3x^2+3x-1\right)-\left(2y\right)^3=\left(x-1\right)^3-\left(2y\right)^3=\left(x-1-2y\right)\left[\left(x-1\right)^2+\left(x-1\right)2y+4y^2\right]\)

Answer 2

minh cung lop 8

a.x^4+3x^3-9x-9

=x^4-9+3x^3-9x

=(x^2-3)(x^2+3)+3x(x^2-3)

=(x^2-3)(x^2+3+3x)

dung no co j cu hoi minh minh chuyen toan,hoa, anh

Answer 3

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