Question

Phân tích da thuc thành nhân tử

A) X^2 - 3x - 4xy +12y

B) X^2 + x - 6

Answer 1

b x²+x-6

=x²+3x-2x-6

=x(x+3)-2(x+3)

= (x-2)(x+3)

Answer 2

a)\(x^2-3x-4xy+12y\)

\(=\left(x^2-3x\right)-\left(4xy-12y\right)\)

\(=x\left(x-3\right)-4y\left(x-3\right)\)

\(=\left(x-3\right)\left(x-4y\right)\)

b)\(x^2+x-6\)

\(=x^2-2x+3x-6\)

\(=\left(x^2-2x\right)+\left(3x-6\right)\)

\(=x\left(x-2\right)+3\left(x-2\right)\)

\(=\left(x-2\right)\left(x+3\right)\)