a) CaCO3--->CaO+CO2
n\(_{CaCO3}=\frac{60}{100}=0,6\left(mol\right)\)
Theo pthh
n\(_{CaO}=n_{CaC_{ }O3}=0,6\left(mol\right)\)
m\(_{CaO}=0,6.56=33,6\left(g\right)\)\
b)m\(_{C_{ }02}=0,6.44=26,4\left(g\right)\)
nCaCO3 = 0,6(mol)
PTHH : CaCO3--->CO2+CaO
=>nCaO = 0,6(mol)
=>mCaO = 0,6 . 56 = 33,6(g)
b,mCO2 = 0,6 . 44 = 26,4(g)