5.
a.
Do \(Ax||Mz\) nên \(\widehat{M_1}=\widehat{MAx}\) (hai góc so le trong)
Mà \(\widehat{MAx}=40^0\Rightarrow\widehat{M_1}=40^0\)
Do \(By||Mz\Rightarrow\widehat{M_2}=\widehat{MBy}\) (so le trong)
Mà \(\widehat{MBy}=30^0\Rightarrow\widehat{M_2}=30^0\)
b.
Ta có:
\(\widehat{AMB}=\widehat{M_1}+\widehat{M_2}\)
\(\widehat{AMB}=40^0+30^0\)
\(\widehat{AMB}=70^0\)
6.
a.
Do \(Mx||Az\Rightarrow\widehat{A_4}=45^0\) (hai góc đồng vị)
Do \(Ny||Az\Rightarrow\widehat{A_3}=55^0\) (hai góc đồng vị)
b.
Ta có:
\(\widehat{MAN}=\widehat{A_4}+\widehat{A_3}\)
\(\widehat{MAN}=55^0+45^0\)
\(\widehat{MAN}=100^0\)