ta có CTHH: \(H^I_x\left(PO_4\right)^{III}_y\)
\(\rightarrow I.x=III.y\rightarrow\dfrac{x}{y}=\dfrac{III}{I}=\dfrac{3}{1}\rightarrow\left[{}\begin{matrix}x=3\\y=1\end{matrix}\right.\)
\(\rightarrow CTHH:H_3PO_4\)
\(PTK=3.1+1.31+4.16=98\left(đvC\right)\)