Question

làm sao để làm A=\(\dfrac{2020}{2019}\) - \(\dfrac{2019}{2018}\) + \(\dfrac{1}{2019x2018}\)

Answer 1

A = \(\dfrac{2020}{2019}\) - \(\dfrac{2019}{2018}\) + \(\dfrac{1}{2019\times2018}\)

A = \(\dfrac{2020}{2019}\) - \(\dfrac{2019}{2018}\) +  ( \(\dfrac{1}{2018}\) - \(\dfrac{1}{2019}\))

A = \(\dfrac{2020}{2019}\) - \(\dfrac{2019}{2018}\) + \(\dfrac{1}{2018}\) - \(\dfrac{1}{2019}\)

A = ( \(\dfrac{2020}{2019}\) - \(\dfrac{1}{2019}\)) - ( \(\dfrac{2019}{2018}\) - \(\dfrac{1}{2018}\))

A = \(\dfrac{2019}{2019}\) - \(\dfrac{2018}{2018}\)

A = 1 - 1

A = 0

Answer 2

ét o ét

Answer 3

thank you

 

Answer 4

khùng luôn