PTHH: \(2HgO\underrightarrow{t^o}2Hg+O_2\\ 0,375mol\rightarrow0,375mol:0,1875mol\)
\(n_{HgO}=\dfrac{81,375}{217}=0,375\left(mol\right)\)
\(m_{Hg}=201.0,375=75,375\left(g\right)\)
\(V_{O_2}=22,4.0,1875=4,2\left(l\right)\)
\(n_{HgO}=\dfrac{81,375}{217}=0,375\left(mol\right)\)
PTHH: \(2HgO-t^o->2Hg+O_2\uparrow\)
Theo PT ta có: \(n_{Hg}=n_{HgO}=0,375\left(mol\right)\)
=> \(m_{Hg}=0,375.201=75,375\left(g\right)\)
Theo PT ta có: \(n_{O_2}=\dfrac{0,375.1}{2}=0,1875\left(mol\right)\)
=> \(V_{O_2}=0,1875.22,4=4,2\left(l\right)\)
\(n_{HgO}=\dfrac{81,375}{217}=0,375\left(mol\right)\)
PTHH: \(2HgO\underrightarrow{t^0}2Hg+O_2\)
Theo PTHH: \(n_{HgO}:n_{Hg}=2:2=1\)
\(\Rightarrow n_{Hg}=n_{HgO}=0,375\left(mol\right)\)
\(\Rightarrow m_{Hg}=0,375.201=75,375\left(g\right)\)
Theo PTHH: \(n_{HgO}:n_{O_2}=2:1\)
\(\Rightarrow n_{O_2}=n_{HgO}.\dfrac{1}{2}=0,375.\dfrac{1}{2}=0,1875\left(mol\right)\)
\(\Rightarrow V_{O_2\left(đktc\right)}=0,1875.22,4=4,2\left(l\right)\)
