nếu q và p là số tự nhiên và 9,062 <q + p <12,998 sau đó pxq = ????
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
If p and q are consecutive natural numbers and 9.062 < p + q<12.998 then pxq =
If p and q are consecutive natural numbers and 9.062 < p + q<12.998 then =
If p and q are consecutive natural numbers and 9.062 < p + q<12.998 then =
if p,q are consecutive natural numbers and 9,062<p+q<12,998 then p+q=?
If a and b are consecutive odd numbers and a>35,7>b then a =
If and a are b consecutive even numbers and a<23.6<b then a
If n is a natural number and n<12.03<n+5 then the greatest value of n is
If n is a natural number and n<12.03<n+5 then the smallest value of n is
If n is a natural number and n < 7,25< n + 3 then the number of values of n is....
If x í a natural number and 2/3<x<6/5 then x = ......