\(\dfrac{2x+8}{4x-5}=\dfrac{-2}{9}\)
\(\Leftrightarrow9\left(2x+8\right)=-2\left(4x-5\right)\)
\(\Leftrightarrow9\left(2x+8\right)+2\left(4x-5\right)=0\)
\(\Leftrightarrow18x+72+8x-10=0\)
\(\Leftrightarrow26x+62=0\)
\(\Leftrightarrow26x=0-62\)
\(\Leftrightarrow26x=-62\)
\(\Leftrightarrow x=-62:26\)
\(\Leftrightarrow x=\dfrac{-31}{13}\)
Vậy \(x=\dfrac{-31}{13}\)