Question

Hoàn thành những thông tin còn thiếu trong bảng sau:

Answer 1

Chất	M(g/mol)	n(mol)	m(g)	V(lít) (đkc)
CO2	\(M_{CO_2}=M_C+2.M_O=12+2.16=44\left(\dfrac{g}{mol}\right)\)	\(n_{CO_2}=\dfrac{m_{CO_2}}{M_{CO_2}}=\dfrac{17,6}{44}=0,4\left(mol\right)\)	17,6 (g)	\(V_{CO_2\left(đkc\right)}=n_{CO_2}.24,79=0,4.24,79=9,916\left(l\right)\)
N2	\(M_{N_2}=2M_N=2.14=28\left(\dfrac{g}{mol}\right)\)	\(n_{N_2}=\dfrac{V_{N_2\left(đkc\right)}}{24,79}=\dfrac{4,958}{24,79}=0,2\left(mol\right)\)	\(m_{N_2}=M_{N_2}.n_{N_2}=28.0,2=5,6\left(g\right)\)	4,958 (l)
H2	\(M_{H_2}=2M_H=2.1=2\left(\dfrac{g}{mol}\right)\)	0,5 (mol)	\(m_{H_2}=M_{H_2}.n_{H_2}=2.0,5=1\left(g\right)\)	\(V_{H_2\left(đkc\right)}=n_{H_2}.24,79=0,5.24,79=12,395\left(l\right)\)