Na2CO3+2HCl=>2NaCl+H20+CO2
K2CO3+2HCl=>2KCl+H20+CO2
nNa2CO3=10.6/106=0.1mol
nK2CO3=6.9/138=0.05mol
=>nCO2đầu=0.1+0.05=0.15mol>0.12 mol
Vậy nCO2pư=0.12mol
=>nHCl=0.12x2=0.24(mol)
=>mHCl=0.24x36.5=8.76(g)
=>m=mddHCl=8.76*100%/5%=175.2(g)