Question

hap thu v lit khi so2 do o dktc 0,088lit dung dich NAOH 3,65 M thu duoc 27,606 gam 2 muoi NAHSO3 va NA2CO3 . Hay xac dinh khoi luong moi muoi sinh ra

Answer 1

Gọi \(\left\{{}\begin{matrix}n_{NaHSO3}:x\left(mol\right)\\n_{Na2SO3}:y\left(mol\right)\end{matrix}\right.\)

Ta có:

\(n_{NaOH}=0,088.3,65=0,3212\left(mol\right)\)

\(NaOH+SO_2\rightarrow NaHSO_3\)

\(2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\)

Giải hệ PT:

\(\left\{{}\begin{matrix}104x+126y=27,606\\x+2y=0,3212\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,18\\y=0,07\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}m_{NaHSO3}=0,08.104=18,72\left(g\right)\\m_{Na2SO3}=27,606-18,72=8,886\left(g\right)\end{matrix}\right.\)