Giải phương trình bằng cách đưa về phương trình tích:
a ) 3 x 2 − 7 x − 10 ⋅ 2 x 2 + ( 1 − 5 ) x + 5 − 3 = 0 b ) x 3 + 3 x 2 − 2 x − 6 = 0 c ) x 2 − 1 ( 0 , 6 x + 1 ) = 0 , 6 x 2 + x d ) x 2 + 2 x − 5 2 = x 2 − x + 5 2
GPT: \(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(1+\sqrt{x^2+7x+10}\right)=3\)
\(6\sqrt{x+5}-30=x^2-7x\)
GPT đi
GPT:
a,\(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(\sqrt{x^2+7x+10}+1\right)=3\)
b,\(x^2+9x+20=2\sqrt{3x+10}\)
GPT:
a .\(x+\sqrt{5+\sqrt{x-1}}=6.\)
b.\(x=\left(2004+\sqrt{x}\right)\left(1-\sqrt{1-\sqrt{x}}\right)^2\)
c. \(3x^2+21x+18+2\sqrt{x^2+7x+7}=2\)
GPT:
1/ \(\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1\)
2/ \(\sqrt[3]{\frac{12x^2+12x+9}{4}}=x+\sqrt[4]{\frac{4x^3-2}{3}}\)
Gpt: \(2x+2\sqrt{x^2+5x}+\sqrt{x+5}+\sqrt{x}=25\)
Gpt: \(5x^2+3x+6=\left(7x+1\right)\sqrt{x^2+3}\)
GPT :
\(2x^2+7x+1+\left(2x-1\right)\sqrt{x^2+1}=0\)