Question

Giúp tôi giải toán:

Tính bằng cách thuận tiện nhất

15 x \(\frac{2121}{4343}\)+ 15 x \(\frac{222222}{434343}\)

Answer 1

\(15x\frac{2121}{4343}+15x\frac{222222}{434343}\)

\(=15x\frac{21}{43}+15x\frac{22}{43}\)

\(=15x\left(\frac{21}{43}+\frac{22}{43}\right)\)

\(=15x1\)

\(=15\)

Answer 2

= 15 x 21/43 + 15x 22/43

= 15 x (21/43 + 22/43)

= 15 x 1 =15

Answer 3

\(15\cdot\frac{2121}{4343}+15\cdot\frac{222222}{434343}\) =\(15\cdot\left(\frac{2121}{4343}+\frac{222222}{434343}\right)\) =\(15\cdot\left(\frac{21}{43}+\frac{22}{43}\right)\)  =\(15\cdot\frac{43}{43}\) =\(15\cdot1=15\)   tish cho mk nhé