Bài 4:
a: \(A=\dfrac{1}{3}\left(\dfrac{4}{5}+\dfrac{6}{5}+2\right)=\dfrac{1}{3}\cdot4=\dfrac{4}{3}\)
b: \(B=\dfrac{1}{8}\left(\dfrac{3}{8}+\dfrac{5}{8}\right)+\dfrac{7}{8}=\dfrac{1}{8}+\dfrac{7}{8}=1\)
c: \(C=\dfrac{4}{19}\left(-\dfrac{5}{6}-\dfrac{7}{12}\right)-\dfrac{40}{57}\)
\(=\dfrac{4}{19}\cdot\dfrac{-17}{12}-\dfrac{40}{57}=-1\)
d: \(D=\dfrac{3\cdot9}{7\cdot26}-\dfrac{1}{182}-\dfrac{1}{7}\)
\(=\dfrac{26}{7\cdot26}-\dfrac{1}{7}=0\)