Bài 4:
b)
a) Ta có: \(\left(2x-3\right)\left(3x^2-x-1\right)\left(3x-1\right)\)
\(=\left(6x^2-2x-9x+3\right)\left(3x^2-x-1\right)\)
\(=\left(6x^2-11x+3\right)\left(3x^2-x-1\right)\)
\(=18x^4-6x^3-6x^2-33x^3+11x^2+11x+9x^2-3x-3\)
\(=18x^4-39x^3+14x^2+8x-3\)
b) Ta có: \(\left(x^2+2x-3\right)\left(x^2+2x+3\right)\)
\(=\left(x^2+2x\right)^2-9\)
\(=x^4+4x^3+4x^2-9\)