( x - 3 ) ⋮ ( x - 1 )
<=> ( x - 1 - 2 ) ⋮ ( x - 1 )
Mà ( x - 1 ) ⋮ ( x - 1 ) nên 2 ⋮ ( x -1 )
x - 1 thuộc Ư(2)
Ư(2) = { 1 ; 2 }
Xét : x - 1 = 1 => x = 2
x - 1 = 2 => x = 3
=> x thuộc { 2 ; 3 }
\(x-3⋮x-1\)
\(\Rightarrow x-1-2⋮x-1\)
\(\Rightarrow-2⋮x-1\)
\(\Rightarrow x-1\in\left\{2,1,-1,-2\right\}\)
\(\Rightarrow x\in\left\{3,2,0,-1\right\}\)
(x-3)\(⋮\)(x-1)
(x-1)\(⋮\)(x-1)
=>[(x-3)-(x-1)]\(⋮\)x-1
=>2\(⋮\)x-1=>x-1\(\in\)Ư(2)={\(\pm\)1,\(\pm\)2}
Ta có bảng sau:
x-1=1 | x=2 |
x-1=-1 | x=0 |
x-1=2 | x=3 |
x-1=-2 | x=-1 |
Vậy x\(\in\){2,0,3,-1}
hok tốt
nhớ k mk ^_^