Lời giải:
$\frac{27}{15}+\frac{6}{8}=\frac{9}{5}+\frac{3}{4}$
$=\frac{9\times 4}{5\times 4}+\frac{3\times 5}{4\times 5}$
$=\frac{36}{20}+\frac{15}{20}=\frac{36+15}{20}=\frac{51}{20}$
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$\frac{2}{9}-\frac{1}{6}=\frac{4}{18}-\frac{3}{18}=\frac{4-3}{18}=\frac{1}{18}$
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$\frac{19}{24}+\frac{7}{18}=\frac{19\times 3}{24\times 3}+\frac{7\times 4}{18\times 4}=\frac{57}{72}+\frac{28}{72}=\frac{57+28}{72}=\frac{85}{72}$
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$\frac{8}{15}-\frac{1}{3}=\frac{8}{15}-\frac{5}{15}=\frac{8-5}{15}=\frac{3}{15}=\frac{1}{5}$




