\(m_C=1,5.80\%=12\left(g\right)\)
\(n_C=\frac{12}{12}=1\left(mol\right)\)
\(C+O_2\underrightarrow{to}CO_2\)
\(n_{O2}=n_C=1\left(mol\right)\Rightarrow V_{O2}=1.22,4=22,4\left(l\right)\)
\(n_{CO2}=n_C=1\left(mol\right)\)
\(\Rightarrow m_{CO2}=1.44=44\left(g\right)\)