\(\dfrac{x-2}{27}+\dfrac{x-3}{26}+\dfrac{x-4}{25}+\dfrac{x-5}{24}+\dfrac{x-44}{5}=1\)
=>\(\left(\dfrac{x-2}{27}-1\right)+\left(\dfrac{x-3}{26}-1\right)+\left(\dfrac{x-4}{25}-1\right)+\left(\dfrac{x-5}{24}-1\right)+\dfrac{x-44}{5}+3=0\)
=>\(\dfrac{x-29}{27}+\dfrac{x-29}{26}+\dfrac{x-29}{25}+\dfrac{x-29}{24}+\dfrac{x-29}{5}=0\)
=>\(\left(x-29\right)\left(\dfrac{1}{27}+\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{5}\right)=0\)
=>x-29=0
=>x=29
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