\(sin2x-sin2x.cosx=0\)
\(\Leftrightarrow sin2x\left(1-cosx\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}sin2x=0\\cosx=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{k\pi}{2}\\x=k2\pi\end{matrix}\right.\)
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