Simplifying
x2 + 2x + -3x + -6 = 0
Reorder the terms:
-6 + 2x + -3x + x2 = 0
Combine terms: 2x + -3x = -1x
-6 + -1x + x2 = 0
Solving
-6 + -1x + x2 = 0
Solving for variable 'x'.
Factor a trinomial.
(-2 + -1x)(3 + -1x) = 0
Subproblem 1
Set the factor '(-2 + -1x)' equal to zero and attempt to solve:
Simplifying
-2 + -1x = 0
Solving
-2 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '2' to each side of the equation.
-2 + 2 + -1x = 0 + 2
Combine terms: -2 + 2 = 0
0 + -1x = 0 + 2
-1x = 0 + 2
Combine terms: 0 + 2 = 2
-1x = 2
Divide each side by '-1'.
x = -2
Simplifying
x = -2
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:
Simplifying
3 + -1x = 0
Solving
3 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3
Combine terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3
Combine terms: 0 + -3 = -3
-1x = -3
Divide each side by '-1'.
x = 3
Simplifying
x = 3
Solution
x = {-2, 3}
Đê pt đc xác đinh <=> \(x-3\ne0\Rightarrow x\ne3\)
\(\frac{\left(x^2+2x\right)-\left(3x+6\right)}{x-3}=0\)
\(\Leftrightarrow\frac{x\left(x+2\right)-3\left(x+2\right)}{x-3}=0\)
\(\Leftrightarrow\frac{\left(x-3\right)\left(x+2\right)}{x-3}=0\)
\(\Leftrightarrow x+2=0\)
\(\Rightarrow x=-2\)
\(\frac{\left(x^2+2x\right)-\left(3x+6\right)}{x-3}=0\)
\(\frac{x\left(x+2\right)-3\left(x+2\right)}{\left(x-3\right)}=0\)
\(\frac{\left(x-3\right)\left(x+2\right)}{x-3}=0\)
\(\Rightarrow\)x+2=0
\(\Rightarrow\)x=-2
