\(\Leftrightarrow\left(2x-1\right)^2-25=12\sqrt{x^2-x-2}-24\)
\(\Leftrightarrow\left(2x-1-5\right)\left(2x-1+5\right)=3\sqrt{2\left(x-2\right)\left(x+1\right)}-24\)ĐK:\(x\ge2\)
\(\Leftrightarrow4\left(x-3\right)\left(x+2\right)-3\sqrt{2\left(x-2\right)\left(x+1\right)}+24=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+2\right)-3\sqrt{\left(x-2\right)\left(x+1\right)}+6=0\)