Question

Giải phương trình

4x² - 12x + 5 = 0

Answer 1

\(4x^2-12x+5=0\)

\(\Leftrightarrow4x^2-10x-2x+5=0\)

\(\Leftrightarrow\left(4x^2-10x\right)-\left(2x-5\right)=0\)

\(\Leftrightarrow2x\left(2x-5\right)-\left(2x-5\right)=0\)

\(\Leftrightarrow\left(2x-5\right)\left(2x-1\right)=0\)

\(\Leftrightarrow x=\dfrac{5}{2}\) hoặc \(x=\dfrac{1}{2}\)

Answer 2

$4x^2-12x+5=0$

\(\Leftrightarrow\left(2x-1\right)\left(2x-5\right)=0\Leftrightarrow\left[{}\begin{matrix}2x-1=0\\2x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{1}{2}\\x=\frac{5}{2}\end{matrix}\right.\)

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