Ta có: \(\frac{x+1}{2}+\frac{x}{3}=\frac{x-1}{4}+\frac{x-2}{5}\)
\(\Leftrightarrow\frac{30\left(x+1\right)}{60}+\frac{20x}{60}=\frac{15\left(x-1\right)}{60}+\frac{12\left(x-2\right)}{60}\)
\(\Leftrightarrow30x+30+20x=15x-15+12x-24\)
\(\Leftrightarrow50x+30=27x-39\)
\(\Leftrightarrow50x+30-27x+39=0\)
\(\Leftrightarrow23x+69=0\)
\(\Leftrightarrow23\left(x+3\right)=0\)
mà \(23\ne0\)
nên x+3=0
hay x=-3
Vậy: x=-3
Đúng 0
Bình luận (0)
\(\frac{x+1}{2}+\frac{x}{3}=\frac{x-1}{4}+\frac{x-2}{5}\)
\(\Leftrightarrow30x+30+20x=15x-15+12x-24\)
\(\Leftrightarrow23x+69=0\Leftrightarrow x=-3\)
Vậy...
Đúng 0
Bình luận (0)
