Question

giải phương trình : \(\sqrt{2x^2+5x+3}=x-1\)

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}2x^2+5x+3-x^2+2x-1=0\\x>=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x^2+7x+2=0\\x>=1\end{matrix}\right.\)

\(\Leftrightarrow x\in\varnothing\)

Answer 2

2x\(^2\)+5x+3=(x-1)\(^2\)⇔2x\(^2\)+5x+3=x\(^2\)-2x+1⇔x\(^2\)+7x+2=0⇔

Answer 3

x=∅