Question

Giải phương trình: \(sin\left(2x-60^o\right)=\dfrac{1}{2}\)

 

 

Answer 1

`sin(2x-60^o )=1/2`

`<=>[(2x-60^o =30^o +k360^o ),(2x-60^2 =150^o +k360^o ):}`

`<=>[(x=45^o +k180^o ),(x=105^o +k180^o ):}`    `(k in ZZ)`

Answer 2

\(\Leftrightarrow\left[{}\begin{matrix}2x-60^0=30^0+k\cdot360^0\\2x-60^0=150^0+k\cdot360^0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=45^0+k\cdot180^0\\x=105^0+k\cdot180^0\end{matrix}\right.\)